What are the solutions to the equation 7b^2-13b=10-4b ?

The solutions to the equation 7b^2-13b=10-4b are b=2,b=-5/7

Find the zeros of 7b^2-13b=10-4b

The zeros of 7b^2-13b=10-4b are b=2,b=-5/7

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7 b^{2} - 13 b = 10 - 4 b

b = 2, b = - \frac{5}{7}

Decimal Notation

b = 2, b = - 0.71428 \dots

Solution steps

7 b^{2} - 13 b = 10 - 4 b

Move

4 b

to the left side

7 b^{2} - 9 b = 10

Move

10

to the left side

7 b^{2} - 9 b - 10 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 7 ( - 10 )}{2 \cdot 7}

(- 9)^{2} - 4 \cdot 7 (- 10) = 19

b_{1, 2} = \frac{- ( - 9 ) \pm 19}{2 \cdot 7}

Separate the solutions

b_{1} = \frac{- ( - 9 ) + 19}{2 \cdot 7}, b_{2} = \frac{- ( - 9 ) - 19}{2 \cdot 7}

b = \frac{- ( - 9 ) + 19}{2 \cdot 7} : 2

b = \frac{- ( - 9 ) - 19}{2 \cdot 7} : - \frac{5}{7}

The solutions to the quadratic equation are:

b = 2, b = - \frac{5}{7}

- x - 3 = 2 x - 6

x^{3} - 11 x^{2} + 36 x - 30

(\frac{3 m ^{2} n ^{7}}{m})^{5}

8 x^{2} - x - 9

3 m^{2} + 9 m + 27

What are the solutions to the equation 7b^2-13b=10-4b ?
The solutions to the equation 7b^2-13b=10-4b are b=2,b=-5/7
Find the zeros of 7b^2-13b=10-4b
The zeros of 7b^2-13b=10-4b are b=2,b=-5/7