What is the answer to (4/3)^{1-x}=5^x ?

The answer to (4/3)^{1-x}=5^x is x=(ln(4/3))/(ln(20/3))

Solve for x: (4/3)^{1-x}=5^x

The solution is x=(ln(4/3))/(ln(20/3))

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(\frac{4}{3})^{1 - x} = 5^{x}

x = \frac{ln ( \frac{4}{3} )}{ln ( \frac{20}{3} )}

Decimal Notation

x = 0.15164 \dots

Solution steps

(\frac{4}{3})^{1 - x} = 5^{x}

Apply exponent rules

(1 - x) ln (\frac{4}{3}) = x ln (5)

Solve

(1 - x) ln (\frac{4}{3}) = x ln (5) : x = \frac{ln ( \frac{4}{3} )}{ln ( \frac{20}{3} )}

x = \frac{ln ( \frac{4}{3} )}{ln ( \frac{20}{3} )}

95 = 1 1^{x}

5^{3 x} = 2 5^{6}

2^{2 x + 2} = 9 (2^{x})^{- 1}

4^{x} = \frac{1}{2}

y, x^{y} - y^{x} = 0

What is the answer to (4/3)^{1-x}=5^x ?
The answer to (4/3)^{1-x}=5^x is x=(ln(4/3))/(ln(20/3))
Solve for x: (4/3)^{1-x}=5^x
The solution is x=(ln(4/3))/(ln(20/3))