What is the answer to 2^{2x-1}=3^{3x+4} ?

The answer to 2^{2x-1}=3^{3x+4} is x=(ln(162))/(2ln(2)-3ln(3))

Solve for x: 2^{2x-1}=3^{3x+4}

The solution is x=(ln(162))/(2ln(2)-3ln(3))

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2^{2 x - 1} = 3^{3 x + 4}

x = \frac{ln ( 162 )}{2 ln ( 2 ) - 3 ln ( 3 )}

Decimal Notation

x = - 2.66430 \dots

Solution steps

2^{2 x - 1} = 3^{3 x + 4}

Apply exponent rules

(2 x - 1) ln (2) = (3 x + 4) ln (3)

Solve

(2 x - 1) ln (2) = (3 x + 4) ln (3) : x = \frac{ln ( 162 )}{2 ln ( 2 ) - 3 ln ( 3 )}

x = \frac{ln ( 162 )}{2 ln ( 2 ) - 3 ln ( 3 )}

1 6^{x} = 1

x, 4^{x} = 1

4^{x} = 50

\frac{1}{4} = 3 2^{x - 4}

2^{(5 + 3 x)} = \frac{1}{16}

What is the answer to 2^{2x-1}=3^{3x+4} ?
The answer to 2^{2x-1}=3^{3x+4} is x=(ln(162))/(2ln(2)-3ln(3))
Solve for x: 2^{2x-1}=3^{3x+4}
The solution is x=(ln(162))/(2ln(2)-3ln(3))