What is the answer to (2^{3x-1})/(2^{x+5)}=2^x ?

The answer to (2^{3x-1})/(2^{x+5)}=2^x is x=6

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(2^{3x-1})/(2^{x+5)}=2^x

\frac{2 ^{3 x - 1}}{2 ^{x + 5}} = 2^{x}

x = 6

Solution steps

\frac{2 ^{3 x - 1}}{2 ^{x + 5}} = 2^{x}

Apply exponent rules

2 x - 6 = x

Solve

2 x - 6 = x : x = 6

x = 6

Verify Solutions:

x = 6

True

The solution is

x = 6

2^{x + 14} = 1 6^{2 x}

8^{- 4} = 4^{- 2 x - 4}

e^{- x} = - \frac{2}{( x + 1 )}

3^{2 x + 5} = 4

y, z x + e^{zy} = x

What is the answer to (2^{3x-1})/(2^{x+5)}=2^x ?
The answer to (2^{3x-1})/(2^{x+5)}=2^x is x=6
Solve for x: (2^{3x-1})/(2^{x+5)}=2^x
The solution is x=6