What is the answer to 5^{x+2}=4 ?

The answer to 5^{x+2}=4 is x=(2ln(2))/(ln(5))-2

Solve for x: 5^{x+2}=4

The solution is x=(2ln(2))/(ln(5))-2

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5^{x + 2} = 4

x = \frac{2 ln ( 2 )}{ln ( 5 )} - 2

Decimal Notation

x = - 1.13864 \dots

Solution steps

5^{x + 2} = 4

Apply exponent rules

(x + 2) ln (5) = ln (4)

Solve

(x + 2) ln (5) = ln (4) : x = \frac{2 ln ( 2 )}{ln ( 5 )} - 2

x = \frac{2 ln ( 2 )}{ln ( 5 )} - 2

4^{4 x - 1} = \frac{1}{2}

4^{3 x + 5} = 8^{4 x - 3}

3^{x} - 12 + 27 \cdot 3^{- x} = 0

9^{4 x} = \frac{1}{27}

3^{x^{2}} \cdot 3 = 3

What is the answer to 5^{x+2}=4 ?
The answer to 5^{x+2}=4 is x=(2ln(2))/(ln(5))-2
Solve for x: 5^{x+2}=4
The solution is x=(2ln(2))/(ln(5))-2