What is the answer to 10^{2x+3}=5 ?

The answer to 10^{2x+3}=5 is x=-(ln(200))/(2ln(10))

Solve for x: 10^{2x+3}=5

The solution is x=-(ln(200))/(2ln(10))

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1 0^{2 x + 3} = 5

x = - \frac{ln ( 200 )}{2 ln ( 10 )}

Decimal Notation

x = - 1.15051 \dots

Solution steps

1 0^{2 x + 3} = 5

Apply exponent rules

(2 x + 3) ln (10) = ln (5)

Solve

(2 x + 3) ln (10) = ln (5) : x = - \frac{ln ( 200 )}{2 ln ( 10 )}

x = - \frac{ln ( 200 )}{2 ln ( 10 )}

2^{n - 6} = 8^{2 - n}

2^{2 x} - 3 \cdot 2^{x + 1} + 8 = 0

4^{x - x^{2}} = \frac{1}{2}

4^{x} + 6^{x} - 2 \cdot 9^{x} = 0

2 7^{x + 3} = 9^{2 x}

What is the answer to 10^{2x+3}=5 ?
The answer to 10^{2x+3}=5 is x=-(ln(200))/(2ln(10))
Solve for x: 10^{2x+3}=5
The solution is x=-(ln(200))/(2ln(10))