What is the answer to (23^{x-6})^{2x+5}=1 ?

The answer to (23^{x-6})^{2x+5}=1 is x=-5/2 ,x=6

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(23^{x-6})^{2x+5}=1

(2 3^{x - 6})^{2 x + 5} = 1

x = - \frac{5}{2}, x = 6

Decimal Notation

x = - 2.5, x = 6

Solution steps

(2 3^{x - 6})^{2 x + 5} = 1

Apply exponent rules

(2 x + 5) ln (2 3^{x - 6}) = ln (1)

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 5 = 0 or ln (2 3^{x - 6}) = 0

Solve

2 x + 5 = 0 : x = - \frac{5}{2}

Solve

ln (2 3^{x - 6}) = 0 : x = 6

x = - \frac{5}{2}, x = 6

32 = 1 (2)^{n - 1}

x, e^{3 - 2 x} = 4

5^{x} = 48

5^{x} = 24

5^{x} = 27

What is the answer to (23^{x-6})^{2x+5}=1 ?
The answer to (23^{x-6})^{2x+5}=1 is x=-5/2 ,x=6
Solve for x: (23^{x-6})^{2x+5}=1
The solution is x=-5/2 ,x=6