What is the answer to 2^{4x-1}=3^x ?

The answer to 2^{4x-1}=3^x is x=(ln(2))/(4ln(2)-ln(3))

Solve for x: 2^{4x-1}=3^x

The solution is x=(ln(2))/(4ln(2)-ln(3))

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2^{4 x - 1} = 3^{x}

x = \frac{ln ( 2 )}{4 ln ( 2 ) - ln ( 3 )}

Decimal Notation

x = 0.41407 \dots

Solution steps

2^{4 x - 1} = 3^{x}

Apply exponent rules

(4 x - 1) ln (2) = x ln (3)

Solve

(4 x - 1) ln (2) = x ln (3) : x = \frac{ln ( 2 )}{4 ln ( 2 ) - ln ( 3 )}

x = \frac{ln ( 2 )}{4 ln ( 2 ) - ln ( 3 )}

2 5^{x - 1} = \frac{1}{125}

3 = 8 (2)^{5 x} - 15

32 = 1 6^{x + 4}

81 = 3 3^{x}

4^{- x} = 256

What is the answer to 2^{4x-1}=3^x ?
The answer to 2^{4x-1}=3^x is x=(ln(2))/(4ln(2)-ln(3))
Solve for x: 2^{4x-1}=3^x
The solution is x=(ln(2))/(4ln(2)-ln(3))