What is the answer to solvefor x,c=50+10^{2-xq} ?

The answer to solvefor x,c=50+10^{2-xq} is x=-(ln(c-50)-2ln(10))/(ln(10)q)

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solvefor x,c=50+10^{2-xq}

solve for

x, c = 50 + 1 0^{2 - x q}

x = - \frac{ln ( c - 50 ) - 2 ln ( 10 )}{ln ( 10 ) q}

Solution steps

c = 50 + 1 0^{2 - x q}

Switch sides

50 + 1 0^{2 - x q} = c

Move

50

to the right side

1 0^{2 - x q} = c - 50

Apply exponent rules

(2 - x q) ln (10) = ln (c - 50)

Solve

(2 - x q) ln (10) = ln (c - 50) : x = - \frac{ln ( c - 50 ) - 2 ln ( 10 )}{ln ( 10 ) q}

x = - \frac{ln ( c - 50 ) - 2 ln ( 10 )}{ln ( 10 ) q}

5^{x^{2}} = 2 5^{x + 4}

5^{x - 1} = 1 3^{3 x}

5000000 = 1000000 e^{0.645 t}

6^{x} = 5 \cdot 3^{x + 1}

What is the answer to solvefor x,c=50+10^{2-xq} ?
The answer to solvefor x,c=50+10^{2-xq} is x=-(ln(c-50)-2ln(10))/(ln(10)q)