What is the answer to 2^x=3^{(x-1)} ?

The answer to 2^x=3^{(x-1)} is x=(ln(3))/(ln(3)-ln(2))

Solve for x: 2^x=3^{(x-1)}

The solution is x=(ln(3))/(ln(3)-ln(2))

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2^{x} = 3^{(x - 1)}

x = \frac{ln ( 3 )}{ln ( 3 ) - ln ( 2 )}

Decimal Notation

x = 2.70951 \dots

Solution steps

2^{x} = 3^{(x - 1)}

Apply exponent rules

x ln (2) = (x - 1) ln (3)

Solve

x ln (2) = (x - 1) ln (3) : x = \frac{ln ( 3 )}{ln ( 3 ) - ln ( 2 )}

x = \frac{ln ( 3 )}{ln ( 3 ) - ln ( 2 )}

\frac{1}{3} = 3^{(2 x + 2)}

4^{x} + 64 = 16 \cdot 2^{x}

b, e^{a x} - e^{b - a x} = c

t = 20 + 70 e^{- t}

x, z = y^{3} e^{x^{2}}

What is the answer to 2^x=3^{(x-1)} ?
The answer to 2^x=3^{(x-1)} is x=(ln(3))/(ln(3)-ln(2))
Solve for x: 2^x=3^{(x-1)}
The solution is x=(ln(3))/(ln(3)-ln(2))