What is the answer to 9^{2x}=27^{x^2-5} ?

The answer to 9^{2x}=27^{x^2-5} is x=3,x=-5/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9^{2x}=27^{x^2-5}

9^{2 x} = 2 7^{x^{2} - 5}

x = 3, x = - \frac{5}{3}

Decimal Notation

x = 3, x = - 1.66666 \dots

Solution steps

9^{2 x} = 2 7^{x^{2} - 5}

Apply exponent rules

4 x = 3 (x^{2} - 5)

Solve

4 x = 3 (x^{2} - 5) : x = 3, x = - \frac{5}{3}

x = 3, x = - \frac{5}{3}

4^{x} + 1 + 4^{x} - 1 = 64

8 1^{p} = 1

5^{2 x} - 30 \cdot 5^{x} + 125 = 0

(\frac{2}{3})^{x} = 2.25

4^{x} + 2^{(x + 2)} = 3

What is the answer to 9^{2x}=27^{x^2-5} ?
The answer to 9^{2x}=27^{x^2-5} is x=3,x=-5/3
Solve for x: 9^{2x}=27^{x^2-5}
The solution is x=3,x=-5/3