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Popular >

2(e^x)+e^{(2x)/2}=0

Solution

2 (e^{x}) + e^{\frac{2 x}{2}} = 0

Solution

x = Undefined - ln (2)

Solution steps

2 (e^{x}) + e^{\frac{2 x}{2}} = 0

Subtract

e^{\frac{2 x}{2}}

from both sides

2 e^{x} + e^{\frac{2 x}{2}} - e^{\frac{2 x}{2}} = 0 - e^{\frac{2 x}{2}}

Simplify

2 e^{x} = - e^{\frac{2 x}{2}}

Apply exponent rules

ln (2) + x = ln (- 1) + \frac{2 x}{2}

Solve

ln (2) + x = ln (- 1) + \frac{2 x}{2} : x =

Undefined

- ln (2)

x = Undefined - ln (2)

Popular Examples

(sqrt(10))^{x+1}=0.01

(10)^{x + 1} = 0.01

4^{2 - x} = 3

2187 = 3^{x}

e^{- 4 x} = 1

solvefor k,n=2^k-1 solve for

k, n = 2^{k} - 1

Frequently Asked Questions (FAQ)

What is the answer to 2(e^x)+e^{(2x)/2}=0 ?
The answer to 2(e^x)+e^{(2x)/2}=0 is x=Undefined-ln(2)