What is the answer to 10^x=41 ?

The answer to 10^x=41 is x=(ln(41))/(ln(10))

The solution is x=(ln(41))/(ln(10))

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10^x=41

1 0^{x} = 41

x = \frac{ln ( 41 )}{ln ( 10 )}

Decimal Notation

x = 1.61278 \dots

Solution steps

1 0^{x} = 41

Apply exponent rules

x ln (10) = ln (41)

Solve

x ln (10) = ln (41) : x = \frac{ln ( 41 )}{ln ( 10 )}

x = \frac{ln ( 41 )}{ln ( 10 )}

x e^{x} = e^{x}

2^{2 x + 1} - 3 \cdot 2^{x} - 2 = 0

2^{x} = \frac{1}{512}

1 0^{x} = 23

x, e^{x} - 5 = 0