What is the answer to 4^{x-3}=(1/8)^{2x+1} ?

The answer to 4^{x-3}=(1/8)^{2x+1} is x= 3/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4^{x-3}=(1/8)^{2x+1}

4^{x - 3} = (\frac{1}{8})^{2 x + 1}

x = \frac{3}{8}

Decimal Notation

x = 0.375

Solution steps

4^{x - 3} = (\frac{1}{8})^{2 x + 1}

Apply exponent rules

2 (x - 3) = - 3 (2 x + 1)

Solve

2 (x - 3) = - 3 (2 x + 1) : x = \frac{3}{8}

x = \frac{3}{8}

6 4^{1 - 2 x} = 0.2 5^{3 x}

4^{1 - x} + 2^{3 - x} - 12 = 0

x = 2^{\frac{x}{2}}

3^{5 x - 1} = 5^{2 x}

8^{x} = 132

What is the answer to 4^{x-3}=(1/8)^{2x+1} ?
The answer to 4^{x-3}=(1/8)^{2x+1} is x= 3/8
Solve for x: 4^{x-3}=(1/8)^{2x+1}
The solution is x= 3/8