What is the answer to 3^{2x}-3^{2x-1}=18 ?

The answer to 3^{2x}-3^{2x-1}=18 is x= 3/2

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3^{2x}-3^{2x-1}=18

3^{2 x} - 3^{2 x - 1} = 18

x = \frac{3}{2}

Decimal Notation

x = 1.5

Solution steps

3^{2 x} - 3^{2 x - 1} = 18

Apply exponent rules

2 x = 3

Solve

2 x = 3 : x = \frac{3}{2}

x = \frac{3}{2}

4^{x} - 2^{x + 1} - 8 = 0

5 e^{7 x} = 3215

5^{2 m + 2} - 10 (5^{m}) = 3

4 + 21 \cdot (e^{- 2027 \cdot x}) = 8

What is the answer to 3^{2x}-3^{2x-1}=18 ?
The answer to 3^{2x}-3^{2x-1}=18 is x= 3/2
Solve for x: 3^{2x}-3^{2x-1}=18
The solution is x= 3/2