What is the answer to 343=72^{x+2} ?

The answer to 343=72^{x+2} is x=(3ln(7))/(ln(72))-2

Solve for x: 343=72^{x+2}

The solution is x=(3ln(7))/(ln(72))-2

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343 = 7 2^{x + 2}

x = \frac{3 ln ( 7 )}{ln ( 72 )} - 2

Decimal Notation

x = - 0.63498 \dots

Solution steps

343 = 7 2^{x + 2}

Apply exponent rules

ln (343) = (x + 2) ln (72)

Solve

ln (343) = (x + 2) ln (72) : x = \frac{3 ln ( 7 )}{ln ( 72 )} - 2

x = \frac{3 ln ( 7 )}{ln ( 72 )} - 2

x, x^{x} = y^{y}

1 6^{2 + x + 1} = 64

- 3 e^{3 x} x - e^{3 x} = 0

3^{2 x} - 2 \cdot 3^{x + 5} + 3^{10} = 0

1 7^{4 - 3 x} = 1

What is the answer to 343=72^{x+2} ?
The answer to 343=72^{x+2} is x=(3ln(7))/(ln(72))-2
Solve for x: 343=72^{x+2}
The solution is x=(3ln(7))/(ln(72))-2