What is the answer to (64)/(16^{3x)}=16^{3x-2} ?

The answer to (64)/(16^{3x)}=16^{3x-2} is x= 7/12

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(64)/(16^{3x)}=16^{3x-2}

\frac{64}{1 6 ^{3 x}} = 1 6^{3 x - 2}

x = \frac{7}{12}

Decimal Notation

x = 0.58333 \dots

Solution steps

\frac{64}{1 6 ^{3 x}} = 1 6^{3 x - 2}

Apply exponent rules

ln (64) - 3 x ln (16) = (3 x - 2) ln (16)

Solve

ln (64) - 3 x ln (16) = (3 x - 2) ln (16) : x = \frac{7}{12}

x = \frac{7}{12}

Verify Solutions:

x = \frac{7}{12}

True

The solution is

x = \frac{7}{12}

2^{x^{2} - 7 x + 12} = 1

100 = e^{x}

8 - 2 e^{- x} = 4

2^{x} = 8190

8^{x^{2} - 3} = 8

What is the answer to (64)/(16^{3x)}=16^{3x-2} ?
The answer to (64)/(16^{3x)}=16^{3x-2} is x= 7/12
Solve for x: (64)/(16^{3x)}=16^{3x-2}
The solution is x= 7/12