What is the answer to 2^{-3x+1}= 1/16 ?

The answer to 2^{-3x+1}= 1/16 is x= 5/3

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2^{-3x+1}= 1/16

2^{- 3 x + 1} = \frac{1}{16}

x = \frac{5}{3}

Decimal Notation

x = 1.66666 \dots

Solution steps

2^{- 3 x + 1} = \frac{1}{16}

Apply exponent rules

- 3 x + 1 = - 4

Solve

- 3 x + 1 = - 4 : x = \frac{5}{3}

x = \frac{5}{3}

e^{7 x} = 23

e^{7 x} = 19

x, \frac{A}{2 B} = C^{x}

8 (8^{x - 1} - 1) = 7 (4^{x} - 2^{x + 1})

2 7^{2 x} = 9^{x + 1}