What is the answer to (x-3)^{x^2+1}=(x-3)^{3x+11} ?

The answer to (x-3)^{x^2+1}=(x-3)^{3x+11} is x=4,x=5

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(x-3)^{x^2+1}=(x-3)^{3x+11}

(x - 3)^{x^{2} + 1} = (x - 3)^{3 x + 11}

x = 4, x = 5

Solution steps

(x - 3)^{x^{2} + 1} = (x - 3)^{3 x + 11}

Apply exponent rules

(x^{2} + 1) ln (x - 3) = (3 x + 11) ln (x - 3)

Solve

(x^{2} + 1) ln (x - 3) = (3 x + 11) ln (x - 3) : x = 4, x = 5

x = 4, x = 5

10 e^{2 x} = 7 \cdot 2^{a x}

216 = 6^{x}

4^{x} = 8^{12}

2^{- 2 (4 + x)} = 2^{x - 1}

e^{5 - 4 x} = 2

What is the answer to (x-3)^{x^2+1}=(x-3)^{3x+11} ?
The answer to (x-3)^{x^2+1}=(x-3)^{3x+11} is x=4,x=5
Solve for x: (x-3)^{x^2+1}=(x-3)^{3x+11}
The solution is x=4,x=5