What is ((2x^3y^2)/(-x^2y^5))^{-2} ?

The solution to ((2x^3y^2)/(-x^2y^5))^{-2} is (y^6)/(4x^2)

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simplify ((2x^3y^2)/(-x^2y^5))^{-2}

simplify

(\frac{2 x ^{3} y ^{2}}{- x ^{2} y ^{5}})^{- 2}

\frac{y ^{6}}{4 x ^{2}}

Solution steps

(\frac{2 x ^{3} y ^{2}}{- x ^{2} y ^{5}})^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(\frac{2 x ^{3} y ^{2}}{- x ^{2} y ^{5}})^{- 2} = \frac{1}{( \frac{2 x ^{3} y ^{2}}{- x ^{2} y ^{5}} ) ^{2}}

= \frac{1}{( \frac{2 x ^{3} y ^{2}}{- x ^{2} y ^{5}} ) ^{2}}

Simplify

(\frac{2 x ^{3} y ^{2}}{- x ^{2} y ^{5}})^{2} : \frac{4 x ^{2}}{y ^{6}}

= \frac{1}{\frac{4 x ^{2}}{y ^{6}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{y ^{6}}{4 x ^{2}}

5 (3 x - x + 8) + 4 x = 41 + 15 x

\frac{3}{4 x} - 6 \leq x - 7

\frac{12 !}{0 ! 12 !} (0.36)^{12} (0.64)^{0}

ln (1.06)

1960

What is ((2x^3y^2)/(-x^2y^5))^{-2} ?
The solution to ((2x^3y^2)/(-x^2y^5))^{-2} is (y^6)/(4x^2)