What is the answer to 32^{2x+3}=16^{x+4} ?

The answer to 32^{2x+3}=16^{x+4} is x= 1/6

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32^{2x+3}=16^{x+4}

3 2^{2 x + 3} = 1 6^{x + 4}

x = \frac{1}{6}

Decimal Notation

x = 0.16666 \dots

Solution steps

3 2^{2 x + 3} = 1 6^{x + 4}

Apply exponent rules

5 (2 x + 3) = 4 (x + 4)

Solve

5 (2 x + 3) = 4 (x + 4) : x = \frac{1}{6}

x = \frac{1}{6}

3 (2^{2 x + 3}) - 43 (2^{x}) + 5 = 0

2^{2 x + 2} + 2^{x + 2} = 3

2 e^{3 x} = 32

9^{x + 1} + 1 = 10 (3 x)

5^{x - 3} = 625

What is the answer to 32^{2x+3}=16^{x+4} ?
The answer to 32^{2x+3}=16^{x+4} is x= 1/6
Solve for x: 32^{2x+3}=16^{x+4}
The solution is x= 1/6