What is the answer to 3^{-x}=2 ?

The answer to 3^{-x}=2 is x=-(ln(2))/(ln(3))

Solve for x: 3^{-x}=2

The solution is x=-(ln(2))/(ln(3))

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3^{- x} = 2

x = - \frac{ln ( 2 )}{ln ( 3 )}

Decimal Notation

x = - 0.63092 \dots

Solution steps

3^{- x} = 2

Apply exponent rules

- x ln (3) = ln (2)

Solve

- x ln (3) = ln (2) : x = - \frac{ln ( 2 )}{ln ( 3 )}

x = - \frac{ln ( 2 )}{ln ( 3 )}

15 + 4^{x} = 31

2^{2 x} - 3 \cdot 2^{x + 2} + 32 = 0

1 \cdot 1 0^{x} = 3

4^{x} + 2^{x} = 8

16384 = 2^{x}