What is the answer to 3*10^{-9}=10^{-x} ?

The answer to 3*10^{-9}=10^{-x} is x=-(ln(3/(10^9)))/(ln(10))

Solve for x: 3*10^{-9}=10^{-x}

The solution is x=-(ln(3/(10^9)))/(ln(10))

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3 \cdot 1 0^{- 9} = 1 0^{- x}

x = - \frac{ln ( \frac{3}{1 0 ^{9}} )}{ln ( 10 )}

Decimal Notation

x = 8.52287 \dots

Solution steps

3 \cdot 1 0^{- 9} = 1 0^{- x}

Apply exponent rules

ln (3 \cdot 1 0^{- 9}) = - x ln (10)

Solve

ln (3 \cdot 1 0^{- 9}) = - x ln (10) : x = - \frac{ln ( \frac{3}{1 0 ^{9}} )}{ln ( 10 )}

x = - \frac{ln ( \frac{3}{1 0 ^{9}} )}{ln ( 10 )}

- e^{x + 4} = - 58

3^{n} = 3 \cdot 9^{3} \cdot 8 1^{2}

e^{a} = a

(x^{2})^{r (x) + 3} = x^{5 r (x) - 6}

8^{x} - 10 = 9

What is the answer to 3*10^{-9}=10^{-x} ?
The answer to 3*10^{-9}=10^{-x} is x=-(ln(3/(10^9)))/(ln(10))
Solve for x: 3*10^{-9}=10^{-x}
The solution is x=-(ln(3/(10^9)))/(ln(10))