What is the answer to 3=20(1/2)^{2x} ?

The answer to 3=20(1/2)^{2x} is x=-(ln(3/20))/(2ln(2))

Solve for x: 3=20(1/2)^{2x}

The solution is x=-(ln(3/20))/(2ln(2))

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3 = 20 (\frac{1}{2})^{2 x}

x = - \frac{ln ( \frac{3}{20} )}{2 ln ( 2 )}

Decimal Notation

x = 1.36848 \dots

Solution steps

3 = 20 (\frac{1}{2})^{2 x}

Switch sides

20 (\frac{1}{2})^{2 x} = 3

Divide both sides by

20

(\frac{1}{2})^{2 x} = \frac{3}{20}

Apply exponent rules

2 x ln (\frac{1}{2}) = ln (\frac{3}{20})

Solve

2 x ln (\frac{1}{2}) = ln (\frac{3}{20}) : x = - \frac{ln ( \frac{3}{20} )}{2 ln ( 2 )}

x = - \frac{ln ( \frac{3}{20} )}{2 ln ( 2 )}

4^{x + 1} + 2^{2 x} = 20

7^{x + 1} - 2 = 0

1 0^{x} + 1 0^{x + 1} - 110 = 0

x, w = 3^{2 x - 5}

2433 = 3^{x}

What is the answer to 3=20(1/2)^{2x} ?
The answer to 3=20(1/2)^{2x} is x=-(ln(3/20))/(2ln(2))
Solve for x: 3=20(1/2)^{2x}
The solution is x=-(ln(3/20))/(2ln(2))