What is the answer to 7^{2x}-11(7^x)+10=0 ?

The answer to 7^{2x}-11(7^x)+10=0 is x=(ln(10))/(ln(7)),x=0

Solve for x: 7^{2x}-11(7^x)+10=0

The solution is x=(ln(10))/(ln(7)),x=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

7^{2 x} - 11 (7^{x}) + 10 = 0

x = \frac{ln ( 10 )}{ln ( 7 )}, x = 0

Decimal Notation

x = 1.18329 \dots, x = 0

Solution steps

7^{2 x} - 11 (7^{x}) + 10 = 0

Apply exponent rules

(7^{x})^{2} - 11 \cdot 7^{x} + 10 = 0

Rewrite the equation with

7^{x} = u

(u)^{2} - 11 u + 10 = 0

Solve

u^{2} - 11 u + 10 = 0 : u = 10, u = 1

u = 10, u = 1

Substitute back

u = 7^{x},

solve for

x

Solve

7^{x} = 10 : x = \frac{ln ( 10 )}{ln ( 7 )}

Solve

7^{x} = 1 : x = 0

x = \frac{ln ( 10 )}{ln ( 7 )}, x = 0

3 \cdot 4^{x} + 4^{x - 1} = 208

2 7^{3 x} = 81

3^{x} mod 17 = 12

5^{x - 3} = 8

3^{x + 2} = 9^{2 x - 1}

What is the answer to 7^{2x}-11(7^x)+10=0 ?
The answer to 7^{2x}-11(7^x)+10=0 is x=(ln(10))/(ln(7)),x=0
Solve for x: 7^{2x}-11(7^x)+10=0
The solution is x=(ln(10))/(ln(7)),x=0