What is the answer to 3^x\mod 17=12 ?

The answer to 3^x\mod 17=12 is x=(ln(\frac{12)/(17 ^6))}{ln(3)}

Solve for x: 3^x\mod 17=12

The solution is x=(ln(\frac{12)/(17 ^6))}{ln(3)}

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3^{x} mod 17 = 12

Solution steps

3^{x} mod 17 = 12

Divide both sides by

mod 17

mod 3 ^{x} = \frac{12}{mod 17}

Multiply both sides by

Divide both sides by

^{6}

Apply exponent rules

Solve

5^{x - 3} = 8

3^{x + 2} = 9^{2 x - 1}

2^{2 x + 3} = 2^{x + 1} + 3

5^{x - 4} = 7^{5 x + 2}

What is the answer to 3^x\mod 17=12 ?
The answer to 3^x\mod 17=12 is x=(ln(\frac{12)/(17 ^6))}{ln(3)}
Solve for x: 3^x\mod 17=12
The solution is x=(ln(\frac{12)/(17 ^6))}{ln(3)}