What are the solutions to the equation 3x^2+5x-6=0 ?

The solutions to the equation 3x^2+5x-6=0 are x=(-5+sqrt(97))/6 ,x=(-5-sqrt(97))/6

Find the zeros of 3x^2+5x-6=0

The zeros of 3x^2+5x-6=0 are x=(-5+sqrt(97))/6 ,x=(-5-sqrt(97))/6

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3 x^{2} + 5 x - 6 = 0

x = \frac{- 5 + 97}{6}, x = \frac{- 5 - 97}{6}

Decimal Notation

x = 0.80814 \dots, x = - 2.47480 \dots

Solution steps

3 x^{2} + 5 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 3 ( - 6 )}{2 \cdot 3}

5^{2} - 4 \cdot 3 (- 6) = 97

x_{1, 2} = \frac{- 5 \pm 97}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 5 + 97}{2 \cdot 3}, x_{2} = \frac{- 5 - 97}{2 \cdot 3}

x = \frac{- 5 + 97}{2 \cdot 3} : \frac{- 5 + 97}{6}

x = \frac{- 5 - 97}{2 \cdot 3} : \frac{- 5 - 97}{6}

The solutions to the quadratic equation are:

x = \frac{- 5 + 97}{6}, x = \frac{- 5 - 97}{6}

- \frac{1}{9}

(\frac{1}{5})^{4}

40 x y - 5 x^{3} + 64 y - 8 x^{2}

- 3 v^{2} - 4 v + 4

(1 6^{\frac{5}{9}} \cdot 5^{\frac{7}{9}})^{- 3}

What are the solutions to the equation 3x^2+5x-6=0 ?
The solutions to the equation 3x^2+5x-6=0 are x=(-5+sqrt(97))/6 ,x=(-5-sqrt(97))/6
Find the zeros of 3x^2+5x-6=0
The zeros of 3x^2+5x-6=0 are x=(-5+sqrt(97))/6 ,x=(-5-sqrt(97))/6