What is the answer to 4*5^x-3=7 ?

The answer to 4*5^x-3=7 is x=(ln(5/2))/(ln(5))

Solve for x: 4*5^x-3=7

The solution is x=(ln(5/2))/(ln(5))

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4 \cdot 5^{x} - 3 = 7

x = \frac{ln ( \frac{5}{2} )}{ln ( 5 )}

Decimal Notation

x = 0.56932 \dots

Solution steps

4 \cdot 5^{x} - 3 = 7

Move

3

to the right side

4 \cdot 5^{x} = 10

Divide both sides by

4

5^{x} = \frac{5}{2}

Apply exponent rules

x ln (5) = ln (\frac{5}{2})

Solve

x ln (5) = ln (\frac{5}{2}) : x = \frac{ln ( \frac{5}{2} )}{ln ( 5 )}

x = \frac{ln ( \frac{5}{2} )}{ln ( 5 )}

8 1^{x} = \frac{1}{27}

8^{5 - x} = 3

2^{3 x - 4} = 11

1 6^{t - 0.25} = \frac{1 6 ^{t}}{2}

1 = e^{1 - x^{2}}

What is the answer to 4*5^x-3=7 ?
The answer to 4*5^x-3=7 is x=(ln(5/2))/(ln(5))
Solve for x: 4*5^x-3=7
The solution is x=(ln(5/2))/(ln(5))