What is the answer to 2(3^{x-1})-5=7 ?

The answer to 2(3^{x-1})-5=7 is x=(ln(6))/(ln(3))+1

Solve for x: 2(3^{x-1})-5=7

The solution is x=(ln(6))/(ln(3))+1

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2 (3^{x - 1}) - 5 = 7

x = \frac{ln ( 6 )}{ln ( 3 )} + 1

Decimal Notation

x = 2.63092 \dots

Solution steps

2 (3^{x - 1}) - 5 = 7

Move

5

to the right side

2 \cdot 3^{x - 1} = 12

Divide both sides by

2

3^{x - 1} = 6

Apply exponent rules

(x - 1) ln (3) = ln (6)

Solve

(x - 1) ln (3) = ln (6) : x = \frac{ln ( 6 )}{ln ( 3 )} + 1

x = \frac{ln ( 6 )}{ln ( 3 )} + 1

8. 1^{4 x + 3} = 1

4^{x - 6} = 64

2^{5 x + 1} + 2^{5 x + 5} = 17

e^{x} = - 2 x

y^{y^{5}} = 100

What is the answer to 2(3^{x-1})-5=7 ?
The answer to 2(3^{x-1})-5=7 is x=(ln(6))/(ln(3))+1
Solve for x: 2(3^{x-1})-5=7
The solution is x=(ln(6))/(ln(3))+1