What is the answer to solvefor x,1=e^{2x-3}-5 ?

The answer to solvefor x,1=e^{2x-3}-5 is x=(ln(6)+3)/2

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solvefor x,1=e^{2x-3}-5

solve for

x, 1 = e^{2 x - 3} - 5

x = \frac{ln ( 6 ) + 3}{2}

Decimal Notation

x = 2.39587 \dots

Solution steps

1 = e^{2 x - 3} - 5

Switch sides

e^{2 x - 3} - 5 = 1

Move

5

to the right side

e^{2 x - 3} = 6

Apply exponent rules

2 x - 3 = ln (6)

Solve

2 x - 3 = ln (6) : x = \frac{ln ( 6 ) + 3}{2}

x = \frac{ln ( 6 ) + 3}{2}

5 = 5 + 16 e^{k (34)}

(\frac{1}{8})^{x} = 512

\frac{- e ^{x} + 2}{3} = 0

2 5^{\frac{x}{2}} = 12 5^{x + 3}

3^{5 x} = 85

What is the answer to solvefor x,1=e^{2x-3}-5 ?
The answer to solvefor x,1=e^{2x-3}-5 is x=(ln(6)+3)/2