What is the answer to 6-3*5^x=2 ?

The answer to 6-3*5^x=2 is x=(ln(4/3))/(ln(5))

Solve for x: 6-3*5^x=2

The solution is x=(ln(4/3))/(ln(5))

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6 - 3 \cdot 5^{x} = 2

x = \frac{ln ( \frac{4}{3} )}{ln ( 5 )}

Decimal Notation

x = 0.17874 \dots

Solution steps

6 - 3 \cdot 5^{x} = 2

Move

6

to the right side

- 3 \cdot 5^{x} = - 4

Divide both sides by

- 3

5^{x} = \frac{4}{3}

Apply exponent rules

x ln (5) = ln (\frac{4}{3})

Solve

x ln (5) = ln (\frac{4}{3}) : x = \frac{ln ( \frac{4}{3} )}{ln ( 5 )}

x = \frac{ln ( \frac{4}{3} )}{ln ( 5 )}

y, b x^{y} = x^{a - y}

343 = 7^{x}

7^{x - 3} + 7^{x - 2} + 7^{x - 1} = 57

5^{x - 1} = 5^{3 x - 11}

3^{2 x - 2} = 5^{x - 1}

What is the answer to 6-3*5^x=2 ?
The answer to 6-3*5^x=2 is x=(ln(4/3))/(ln(5))
Solve for x: 6-3*5^x=2
The solution is x=(ln(4/3))/(ln(5))