What is the answer to 121^{2x}=11^{x+3} ?

The answer to 121^{2x}=11^{x+3} is x=1

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121^{2x}=11^{x+3}

12 1^{2 x} = 1 1^{x + 3}

x = 1

Solution steps

12 1^{2 x} = 1 1^{x + 3}

Apply exponent rules

4 x = x + 3

Solve

4 x = x + 3 : x = 1

x = 1

x, 3^{3 x - 2} = 9^{x}

a, 2^{a} = 3^{b}

5^{2 x} - 5^{x} - 6 = 0

2 5^{x} = 5^{x} + 6

5^{x - 3} = 2 5^{x - 5}

What is the answer to 121^{2x}=11^{x+3} ?
The answer to 121^{2x}=11^{x+3} is x=1
Solve for x: 121^{2x}=11^{x+3}
The solution is x=1