What is the answer to -2=(2pi)/((e^{-c)+1)} ?

The answer to -2=(2pi)/((e^{-c)+1)} is No Solution for c\in\mathbb{R}

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-2=(2pi)/((e^{-c)+1)}

- 2 = \frac{2 π}{( e ^{- c} + 1 )}

No Solution for c \in R

Solution steps

- 2 = \frac{2 π}{( e ^{- c} + 1 )}

Multiply both sides by

e^{- c} + 1

- 2 (e^{- c} + 1) = \frac{2 π}{e ^{- c} + 1} (e^{- c} + 1)

Simplify

- 2 (e^{- c} + 1) = 2 π

Divide both sides by

- 2

e^{- c} + 1 = - π

Move

1

to the right side

e^{- c} = - π - 1

a^{f (c)}

cannot be zero or negative for

c \in R

No Solution for c \in R

8 1^{x} = 63

4^{- 2 x - 1} = 16

3^{(- x + 1)} = \frac{1}{81}

e^{2 z} + e^{z} + 1 = 0

e^{x^{2}} = 2 e^{x}

What is the answer to -2=(2pi)/((e^{-c)+1)} ?
The answer to -2=(2pi)/((e^{-c)+1)} is No Solution for c\in\mathbb{R}