What is the answer to 3500(1+0.25)^{-n}=500 ?

The answer to 3500(1+0.25)^{-n}=500 is n=(ln(7))/(ln(1.25))

Solve for n: 3500(1+0.25)^{-n}=500

The solution is n=(ln(7))/(ln(1.25))

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3500 (1 + 0.25)^{- n} = 500

n = \frac{ln ( 7 )}{ln ( 1.25 )}

Decimal Notation

n = 8.72044 \dots

Solution steps

3500 (1 + 0.25)^{- n} = 500

Divide both sides by

3500

(1 + 0.25)^{- n} = \frac{1}{7}

Apply exponent rules

- n ln (1 + 0.25) = ln (\frac{1}{7})

Solve

- n ln (1 + 0.25) = ln (\frac{1}{7}) : n = \frac{ln ( 7 )}{ln ( 1.25 )}

n = \frac{ln ( 7 )}{ln ( 1.25 )}

x, y = e^{k x}

4^{2 x - 1} = 1024

5^{5 x - 4} = 35

4^{x + 1} = 2 - 7 (2^{x})

3^{2 x} - 7 \cdot 3^{x} = 18

What is the answer to 3500(1+0.25)^{-n}=500 ?
The answer to 3500(1+0.25)^{-n}=500 is n=(ln(7))/(ln(1.25))
Solve for n: 3500(1+0.25)^{-n}=500
The solution is n=(ln(7))/(ln(1.25))