What is the answer to 27^{2x+3}=9^{x/5} ?

The answer to 27^{2x+3}=9^{x/5} is x=-45/28

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27^{2x+3}=9^{x/5}

2 7^{2 x + 3} = 9^{\frac{x}{5}}

x = - \frac{45}{28}

Decimal Notation

x = - 1.60714 \dots

Solution steps

2 7^{2 x + 3} = 9^{\frac{x}{5}}

Apply exponent rules

3 (2 x + 3) = \frac{2 x}{5}

Solve

3 (2 x + 3) = \frac{2 x}{5} : x = - \frac{45}{28}

x = - \frac{45}{28}

e^{x - 1} - 1.5 x = 0

(\frac{1}{100})^{2 x} = 1

e^{x} - 4 e^{- x} = 3

3^{2 - x} = \frac{2 7 ^{x + 1}}{9}

What is the answer to 27^{2x+3}=9^{x/5} ?
The answer to 27^{2x+3}=9^{x/5} is x=-45/28
Solve for x: 27^{2x+3}=9^{x/5}
The solution is x=-45/28