What is the answer to 3^{2-5x}=8(9^{x-1}) ?

The answer to 3^{2-5x}=8(9^{x-1}) is x=(4ln(3)-3ln(2))/(7ln(3))

Solve for x: 3^{2-5x}=8(9^{x-1})

The solution is x=(4ln(3)-3ln(2))/(7ln(3))

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3^{2 - 5 x} = 8 (9^{x - 1})

x = \frac{4 ln ( 3 ) - 3 ln ( 2 )}{7 ln ( 3 )}

Decimal Notation

x = 0.30103 \dots

Solution steps

3^{2 - 5 x} = 8 (9^{x - 1})

Apply exponent rules

(2 - 5 x) ln (3) = ln (8) + 2 (x - 1) ln (3)

Solve

(2 - 5 x) ln (3) = ln (8) + 2 (x - 1) ln (3) : x = \frac{4 ln ( 3 ) - 3 ln ( 2 )}{7 ln ( 3 )}

x = \frac{4 ln ( 3 ) - 3 ln ( 2 )}{7 ln ( 3 )}

e^{2 x} - e^{x} - 132 = 0

83 = 1 1^{x}

15000 = 2370.56 e^{0.04 x}

2^{5 x - 3} = 14

5^{x - 1} = (\frac{1}{25})^{x}

What is the answer to 3^{2-5x}=8(9^{x-1}) ?
The answer to 3^{2-5x}=8(9^{x-1}) is x=(4ln(3)-3ln(2))/(7ln(3))
Solve for x: 3^{2-5x}=8(9^{x-1})
The solution is x=(4ln(3)-3ln(2))/(7ln(3))