What is the answer to 3^{27^{x-2}}=9^{9^{x+1}} ?

The answer to 3^{27^{x-2}}=9^{9^{x+1}} is x=(ln(2)+8ln(3))/(ln(3))

Solve for x: 3^{27^{x-2}}=9^{9^{x+1}}

The solution is x=(ln(2)+8ln(3))/(ln(3))

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3^{2 7^{x - 2}} = 9^{9^{x + 1}}

x = \frac{ln ( 2 ) + 8 ln ( 3 )}{ln ( 3 )}

Decimal Notation

x = 8.63092 \dots

Solution steps

3^{2 7^{x - 2}} = 9^{9^{x + 1}}

Apply exponent rules

3 (x - 2) ln (3) = ln (2) + 2 (x + 1) ln (3)

Solve

3 (x - 2) ln (3) = ln (2) + 2 (x + 1) ln (3) : x = \frac{ln ( 2 ) + 8 ln ( 3 )}{ln ( 3 )}

x = \frac{ln ( 2 ) + 8 ln ( 3 )}{ln ( 3 )}

2 = (\frac{1}{4})^{x}

57 = 5 e^{0.02 \cdot x}

100 0^{x} = 0.1

x, z = e^{\frac{y}{x}}

x^{4 x} = 4

What is the answer to 3^{27^{x-2}}=9^{9^{x+1}} ?
The answer to 3^{27^{x-2}}=9^{9^{x+1}} is x=(ln(2)+8ln(3))/(ln(3))
Solve for x: 3^{27^{x-2}}=9^{9^{x+1}}
The solution is x=(ln(2)+8ln(3))/(ln(3))