What is the answer to 9^{3p}=27^{1-3p} ?

The answer to 9^{3p}=27^{1-3p} is p= 1/5

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9^{3p}=27^{1-3p}

9^{3 p} = 2 7^{1 - 3 p}

p = \frac{1}{5}

Decimal Notation

p = 0.2

Solution steps

9^{3 p} = 2 7^{1 - 3 p}

Apply exponent rules

6 p = 3 (1 - 3 p)

Solve

6 p = 3 (1 - 3 p) : p = \frac{1}{5}

p = \frac{1}{5}

e^{x - 1} - 2 = 0

2^{x - 1} = 3^{2 x + 1}

\frac{5 ^{2 x} - 1}{5 ^{x} + 1} = 4

8^{1 - 2 x} = 16

ln (e^{2 x}) = 2 x

What is the answer to 9^{3p}=27^{1-3p} ?
The answer to 9^{3p}=27^{1-3p} is p= 1/5
Solve for p: 9^{3p}=27^{1-3p}
The solution is p= 1/5