What is the answer to 63=33^x ?

The answer to 63=33^x is x=(ln(63))/(ln(33))

The solution is x=(ln(63))/(ln(33))

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63=33^x

63 = 3 3^{x}

x = \frac{ln ( 63 )}{ln ( 33 )}

Decimal Notation

x = 1.18493 \dots

Solution steps

63 = 3 3^{x}

Apply exponent rules

ln (63) = x ln (33)

Solve

ln (63) = x ln (33) : x = \frac{ln ( 63 )}{ln ( 33 )}

x = \frac{ln ( 63 )}{ln ( 33 )}

9^{6} = (3^{2})^{2 x - 2}

6^{x} = 3^{2 x} - 2^{2 x}

7^{2 x} - 56 \cdot 7^{x} + 343 = 0

4^{x} - 1 6^{x - 2} = 0

\frac{15}{1 + 2 e ^{- 0.5 n}} = 1.8