What is the answer to 0.2^{x+1}=0.6 ?

The answer to 0.2^{x+1}=0.6 is x=(ln(0.6))/(ln(0.2))-1

Solve for x: 0.2^{x+1}=0.6

The solution is x=(ln(0.6))/(ln(0.2))-1

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0. 2^{x + 1} = 0.6

x = \frac{ln ( 0.6 )}{ln ( 0.2 )} - 1

Decimal Notation

x = - 0.68260 \dots

Solution steps

0. 2^{x + 1} = 0.6

Apply exponent rules

(x + 1) ln (0.2) = ln (0.6)

Solve

(x + 1) ln (0.2) = ln (0.6) : x = \frac{ln ( 0.6 )}{ln ( 0.2 )} - 1

x = \frac{ln ( 0.6 )}{ln ( 0.2 )} - 1

135 = 20 + 1130 e^{30 k}

2^{x} + 2^{4 - x} = 17

2^{x^{2} - 2 x + 3} = 4

x^{x} = (x)^{x}

2^{x + 3} = 4^{x - 2}

What is the answer to 0.2^{x+1}=0.6 ?
The answer to 0.2^{x+1}=0.6 is x=(ln(0.6))/(ln(0.2))-1
Solve for x: 0.2^{x+1}=0.6
The solution is x=(ln(0.6))/(ln(0.2))-1