What is the answer to solvefor y=b+ae^{-x},x ?

The answer to solvefor y=b+ae^{-x},x is x=-ln((y-b)/a)

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solvefor y=b+ae^{-x},x

solve for

y = b + a e^{- x}, x

x = - ln (\frac{y - b}{a})

Solution steps

y = b + a e^{- x}

Switch sides

b + a e^{- x} = y

Move

b

to the right side

a e^{- x} = y - b

Divide both sides by

a

e^{- x} = \frac{y - b}{a}

Apply exponent rules

- x = ln (\frac{y - b}{a})

Solve

- x = ln (\frac{y - b}{a}) : x = - ln (\frac{y - b}{a})

x = - ln (\frac{y - b}{a})

x, e^{x^{2} + 1} = 5 e^{- x}

4^{3 x - 15} - 64 = 0

2^{x^{2}} = 8

64 = 3 2^{- x + 2}

ln (e^{x}) = 15

What is the answer to solvefor y=b+ae^{-x},x ?
The answer to solvefor y=b+ae^{-x},x is x=-ln((y-b)/a)