What is the answer to 2^{x-1}=3^{2x-1} ?

The answer to 2^{x-1}=3^{2x-1} is x=(ln(3)-ln(2))/(2ln(3)-ln(2))

Solve for x: 2^{x-1}=3^{2x-1}

The solution is x=(ln(3)-ln(2))/(2ln(3)-ln(2))

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2^{x - 1} = 3^{2 x - 1}

x = \frac{ln ( 3 ) - ln ( 2 )}{2 ln ( 3 ) - ln ( 2 )}

Decimal Notation

x = 0.26957 \dots

Solution steps

2^{x - 1} = 3^{2 x - 1}

Apply exponent rules

(x - 1) ln (2) = (2 x - 1) ln (3)

Solve

(x - 1) ln (2) = (2 x - 1) ln (3) : x = \frac{ln ( 3 ) - ln ( 2 )}{2 ln ( 3 ) - ln ( 2 )}

x = \frac{ln ( 3 ) - ln ( 2 )}{2 ln ( 3 ) - ln ( 2 )}

y, (\frac{1}{2})^{y} = x

1 6^{x} - 5 \cdot 4^{x} = 24

3^{2 c + 1} = 28 \cdot 3^{c} - 9

9^{x^{2} - x - 4} = 3^{6 x + 2}

2^{2 x} + 2^{x} = 12

What is the answer to 2^{x-1}=3^{2x-1} ?
The answer to 2^{x-1}=3^{2x-1} is x=(ln(3)-ln(2))/(2ln(3)-ln(2))
Solve for x: 2^{x-1}=3^{2x-1}
The solution is x=(ln(3)-ln(2))/(2ln(3)-ln(2))