What is the answer to e^{-x^2}-0.5=0 ?

The answer to e^{-x^2}-0.5=0 is x=sqrt(-ln(0.5)),x=-sqrt(-ln(0.5))

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e^{-x^2}-0.5=0

e^{- x^{2}} - 0.5 = 0

x = - ln (0.5), x = - - ln (0.5)

Decimal Notation

x = 0.83255 \dots, x = - 0.83255 \dots

Solution steps

e^{- x^{2}} - 0.5 = 0

Add

0.5

to both sides

e^{- x^{2}} - 0.5 + 0.5 = 0 + 0.5

Simplify

e^{- x^{2}} = 0.5

Apply exponent rules

- x^{2} = ln (0.5)

Solve

- x^{2} = ln (0.5) : x = - ln (0.5), x = - - ln (0.5)

x = - ln (0.5), x = - - ln (0.5)

10 = 58 \cdot e^{- 90 k} + 2

x ln (e^{x}) + x = 12

x^{10} = 2^{x}

8^{5 x - 7} = 9^{2 x - 3}

0.2 = (\frac{4}{5})^{x}

What is the answer to e^{-x^2}-0.5=0 ?
The answer to e^{-x^2}-0.5=0 is x=sqrt(-ln(0.5)),x=-sqrt(-ln(0.5))