What is the answer to 2^{x^3}=128^x ?

The answer to 2^{x^3}=128^x is x=0,x=-sqrt(7),x=sqrt(7)

Solve for x: 2^{x^3}=128^x

The solution is x=0,x=-sqrt(7),x=sqrt(7)

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2^{x^{3}} = 12 8^{x}

x = 0, x = - 7, x = 7

Decimal Notation

x = 0, x = - 2.64575 \dots, x = 2.64575 \dots

Solution steps

2^{x^{3}} = 12 8^{x}

Apply exponent rules

x^{3} = 7 x

Solve

x^{3} = 7 x : x = 0, x = - 7, x = 7

x = 0, x = - 7, x = 7

4 e^{2 x} + 3 e^{x} = 1

6^{2 x - 1} + 180 = 6^{2 x}

3^{x + 2} = 3^{2 x - 5}

2 (2^{2 x}) + 4 = 9 (2^{x})

\frac{40}{1 + e ^{- x}} = 2

What is the answer to 2^{x^3}=128^x ?
The answer to 2^{x^3}=128^x is x=0,x=-sqrt(7),x=sqrt(7)
Solve for x: 2^{x^3}=128^x
The solution is x=0,x=-sqrt(7),x=sqrt(7)