What is the answer to 4*2^{-t/5}=288 ?

The answer to 4*2^{-t/5}=288 is t=-(5ln(72))/(ln(2))

Solve for t: 4*2^{-t/5}=288

The solution is t=-(5ln(72))/(ln(2))

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4 \cdot 2^{- \frac{t}{5}} = 288

t = - \frac{5 ln ( 72 )}{ln ( 2 )}

Decimal Notation

t = - 30.84962 \dots

Solution steps

4 \cdot 2^{- \frac{t}{5}} = 288

Divide both sides by

4

2^{- \frac{t}{5}} = 72

Apply exponent rules

- \frac{t}{5} ln (2) = ln (72)

Solve

- \frac{t}{5} ln (2) = ln (72) : t = - \frac{5 ln ( 72 )}{ln ( 2 )}

t = - \frac{5 ln ( 72 )}{ln ( 2 )}

77 = 1 1^{x}

y, e^{x + y} = x

14 (8)^{x} = 7

3^{2 x} + 3^{x} = 20

2^{(- x)} + 2^{x} = 5

What is the answer to 4*2^{-t/5}=288 ?
The answer to 4*2^{-t/5}=288 is t=-(5ln(72))/(ln(2))
Solve for t: 4*2^{-t/5}=288
The solution is t=-(5ln(72))/(ln(2))