What is the answer to 20*2^x=5*3^x ?

The answer to 20*2^x=5*3^x is x=(2ln(2))/(ln(3)-ln(2))

Solve for x: 20*2^x=5*3^x

The solution is x=(2ln(2))/(ln(3)-ln(2))

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20 \cdot 2^{x} = 5 \cdot 3^{x}

x = \frac{2 ln ( 2 )}{ln ( 3 ) - ln ( 2 )}

Decimal Notation

x = 3.41902 \dots

Solution steps

20 \cdot 2^{x} = 5 \cdot 3^{x}

Apply exponent rules

ln (20) + x ln (2) = ln (5) + x ln (3)

Solve

ln (20) + x ln (2) = ln (5) + x ln (3) : x = \frac{2 ln ( 2 )}{ln ( 3 ) - ln ( 2 )}

x = \frac{2 ln ( 2 )}{ln ( 3 ) - ln ( 2 )}

25 e^{10 k} = 50

380 = 760 \cdot e^{(- 144) \cdot x}

t, x = e^{t} - 1

t, x = e^{t} - 5

3^{2 x - 8} = 1

What is the answer to 20*2^x=5*3^x ?
The answer to 20*2^x=5*3^x is x=(2ln(2))/(ln(3)-ln(2))
Solve for x: 20*2^x=5*3^x
The solution is x=(2ln(2))/(ln(3)-ln(2))