What is the answer to 3^{x+2}=18 ?

The answer to 3^{x+2}=18 is x=(ln(18))/(ln(3))-2

Solve for x: 3^{x+2}=18

The solution is x=(ln(18))/(ln(3))-2

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3^{x + 2} = 18

x = \frac{ln ( 18 )}{ln ( 3 )} - 2

Decimal Notation

x = 0.63092 \dots

Solution steps

3^{x + 2} = 18

Apply exponent rules

(x + 2) ln (3) = ln (18)

Solve

(x + 2) ln (3) = ln (18) : x = \frac{ln ( 18 )}{ln ( 3 )} - 2

x = \frac{ln ( 18 )}{ln ( 3 )} - 2

1.1 2^{x} = 2

8000 = 500 e^{l n (\frac{12}{5}) t}

4^{3 x - 5} = \frac{1}{256}

3000 = 3 \cdot 1 0^{x}

x, e^{- I n x} = 0.2

What is the answer to 3^{x+2}=18 ?
The answer to 3^{x+2}=18 is x=(ln(18))/(ln(3))-2
Solve for x: 3^{x+2}=18
The solution is x=(ln(18))/(ln(3))-2