What is the answer to 7^{(x+2)}=98 ?

The answer to 7^{(x+2)}=98 is x=(ln(98))/(ln(7))-2

Solve for x: 7^{(x+2)}=98

The solution is x=(ln(98))/(ln(7))-2

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7^{(x + 2)} = 98

x = \frac{ln ( 98 )}{ln ( 7 )} - 2

Decimal Notation

x = 0.35620 \dots

Solution steps

7^{(x + 2)} = 98

Apply exponent rules

(x + 2) ln (7) = ln (98)

Solve

(x + 2) ln (7) = ln (98) : x = \frac{ln ( 98 )}{ln ( 7 )} - 2

x = \frac{ln ( 98 )}{ln ( 7 )} - 2

x, e^{x} - y = 0

1 6^{x + 2} = \frac{1}{4}

(x - 2)^{x^{2} - 2 x} = (x - 2)^{x + 4}

7^{5 x - 4} = 14

2^{2 x} = n + 1

What is the answer to 7^{(x+2)}=98 ?
The answer to 7^{(x+2)}=98 is x=(ln(98))/(ln(7))-2
Solve for x: 7^{(x+2)}=98
The solution is x=(ln(98))/(ln(7))-2