What is the answer to 2^{4x-1}=3^{5-2x} ?

The answer to 2^{4x-1}=3^{5-2x} is x=(ln(486))/(2ln(12))

Solve for x: 2^{4x-1}=3^{5-2x}

The solution is x=(ln(486))/(2ln(12))

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2^{4 x - 1} = 3^{5 - 2 x}

x = \frac{ln ( 486 )}{2 ln ( 12 )}

Decimal Notation

x = 1.24475 \dots

Solution steps

2^{4 x - 1} = 3^{5 - 2 x}

Apply exponent rules

(4 x - 1) ln (2) = (5 - 2 x) ln (3)

Solve

(4 x - 1) ln (2) = (5 - 2 x) ln (3) : x = \frac{ln ( 486 )}{2 ln ( 12 )}

x = \frac{ln ( 486 )}{2 ln ( 12 )}

2^{4 x + 3} = 6

e^{2 x} + 42 = - 13 e^{x}

2^{3 x + 1} \cdot 8^{x - 1} = 128

e^{3 - 2 x} = 8 - 3 x

2^{4 x + 3} = 512

What is the answer to 2^{4x-1}=3^{5-2x} ?
The answer to 2^{4x-1}=3^{5-2x} is x=(ln(486))/(2ln(12))
Solve for x: 2^{4x-1}=3^{5-2x}
The solution is x=(ln(486))/(2ln(12))