What is the answer to 5^{2x}=3^{3x+1} ?

The answer to 5^{2x}=3^{3x+1} is x=(ln(3))/(2ln(5)-3ln(3))

Solve for x: 5^{2x}=3^{3x+1}

The solution is x=(ln(3))/(2ln(5)-3ln(3))

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5^{2 x} = 3^{3 x + 1}

x = \frac{ln ( 3 )}{2 ln ( 5 ) - 3 ln ( 3 )}

Decimal Notation

x = - 14.27491 \dots

Solution steps

5^{2 x} = 3^{3 x + 1}

Apply exponent rules

2 x ln (5) = (3 x + 1) ln (3)

Solve

2 x ln (5) = (3 x + 1) ln (3) : x = \frac{ln ( 3 )}{2 ln ( 5 ) - 3 ln ( 3 )}

x = \frac{ln ( 3 )}{2 ln ( 5 ) - 3 ln ( 3 )}

2^{x + 2} - 2^{x + 5} + 7 = 0

3^{n} = 27

95 = 2 7^{x}

2^{2 x - 5} = 16

\frac{10}{2 ^{x}} = 0.001

What is the answer to 5^{2x}=3^{3x+1} ?
The answer to 5^{2x}=3^{3x+1} is x=(ln(3))/(2ln(5)-3ln(3))
Solve for x: 5^{2x}=3^{3x+1}
The solution is x=(ln(3))/(2ln(5)-3ln(3))